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Nov 29, 2010 at 18:55 comment added Kevin Buzzard Yes definitely the $S_i$ must be finite! The theorem is completely false otherwise---just take a standard counterexample to the Hasse principle like $3x^3+4y^3+5z^3=0$.
Nov 29, 2010 at 18:46 comment added Makhalan Duff Well, if S_2 is the set of all finite places, and you have a number field unramified over all of S_2, then that number field must equal Q. My guess is Brian's right.
Nov 29, 2010 at 18:41 comment added Kevin Buzzard If this is the usual Moret-Bailly result that these modularity lifting theorem guys apply, then all it says is that there is a K-point for some number field K in which all primes in a given finite set split. It certainly can't control the degree of K.
Nov 29, 2010 at 18:35 comment added Makhalan Duff No, but that would make sense.
Nov 29, 2010 at 18:29 comment added BCnrd The two sets $S_i$ should be finite if I remember correctly. Have you looked at the original paper where Moret-Bailly proved his result?
Nov 29, 2010 at 18:21 history asked Makhalan Duff CC BY-SA 2.5