Timeline for Are the extra vertices in Nakajima's doubling of a quiver related to Langlands duality?
Current License: CC BY-SA 2.5
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 1, 2010 at 5:31 | comment | added | Allen Knutson | @Sasha: I was probably being too glib in hoping to capture that with the phrase "a moduli space". | |
| Dec 1, 2010 at 4:28 | comment | added | Ben Webster♦ | I would say I'm not very optimistic about this idea; I suppose it's worth a little thinking, but it doesn't match my understanding of this story at all. | |
| Dec 1, 2010 at 4:27 | comment | added | Ben Webster♦ | There is a new graph that the Nakajima quiver variety is the moduli of representations of, but one gets it by adding one vertex, and connecting each old vertex to the new one by w_i edges (and then doubling everything). | |
| Dec 1, 2010 at 3:22 | comment | added | Sasha Kirillov | A correction: $M(v,w)$ is not exactly the moduli space of reps of $Q^\heartsuit$. Namely, its points are representations of $Q^\heartsuit$ but the notion of isomorphism is different: points correspond to orbits of $GL(v)$ action, not $GL(v)\times GL(w)$ action. | |
| Dec 1, 2010 at 2:11 | history | edited | Allen Knutson | CC BY-SA 2.5 |
added 3 characters in body
|
| Nov 30, 2010 at 3:23 | history | edited | Allen Knutson | CC BY-SA 2.5 |
added 149 characters in body
|
| Nov 29, 2010 at 23:24 | comment | added | Jim Humphreys | These types of questions are intriguing, but at the same time Langlands duality is most visible in settings where there are two root lengths. Still, I don't know what to expect here. | |
| Nov 29, 2010 at 15:58 | history | asked | Allen Knutson | CC BY-SA 2.5 |