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Aug 13 at 19:42 history became hot network question
Aug 13 at 12:52 comment added Ali Taghavi @GabeK Yes I see, thank you
Aug 13 at 12:51 comment added Gabe K It should definitely be there, but I don’t have a copy on hand to verify. The intuition that a broad class of metrics admit KE metrics is that it should be equivalent to some algebraic condition and I’ve heard experts say that “most” manifolds should satisfy it. However, this is not my area of expertise and there are certainly counterexamples, so I’m not sure how precise this is.
Aug 13 at 12:47 vote accept Ali Taghavi
Aug 13 at 12:24 comment added Ali Taghavi @GabeK I guess the reference is Griffith& Harris, yes?
Aug 13 at 12:14 answer added Gabe K timeline score: 4
Aug 13 at 12:02 history edited Ali Taghavi CC BY-SA 4.0
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Aug 13 at 12:02 comment added Gabe K A very simple example is $\mathbb{CP}^1 \times \mathbb{CP}^1$, but in general one should expect a very broad class (though not all) of Kahler manifolds to admit Einstein metrics. On the other hand, a metric has constant holomorphic sectional curvature only if it is covered by $\mathbb{CP}^n$, $\mathbb{C}^n$ or $\mathbb{CH}^n$ (I.e., the complex space forms).
Aug 13 at 12:01 history edited Ali Taghavi CC BY-SA 4.0
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Aug 13 at 11:52 history edited Ali Taghavi CC BY-SA 4.0
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Aug 13 at 11:40 history asked Ali Taghavi CC BY-SA 4.0