Skip to main content
6 events
when toggle format what by license comment
Aug 13 at 14:59 comment added joro @NoamD.Elkies I asked stronger result conjecture: mathoverflow.net/questions/476863/…
Aug 13 at 6:30 comment added joro @NoamD.Elkies Many thanks for the verification. If someone else is verifying, computing only the root number is significantly faster than computing the analytic (or algebraic) rank.
Aug 12 at 21:35 comment added Noam D. Elkies Confirmed for $0 < k < 10^4$, which automatically gives the same result for all nonzero $k$ with $|k| < 10^4$ because for these curves the $d$ and $-2d$ twists are isogenous. Moreover, in each case at least one of the four ranks is even. But it's not just a parity obstruction: each of 1, 2, or 3 odd-rank twists arises about 1/3 of the time.
Aug 12 at 18:36 history edited joro CC BY-SA 4.0
typos
Aug 12 at 18:17 history edited joro CC BY-SA 4.0
Added root number
Aug 12 at 16:51 history answered joro CC BY-SA 4.0