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Aug 13 at 8:15 comment added Fedor Ushakov yes, that's correct, but I haven't been able to use it yet
Aug 13 at 3:37 comment added Sam Hopkins Okay, denoting by $M(G)$ the bipartite adjacency matrix of a bipartite graph $G$, it should actually be something like $M(T) = M(G) \otimes M(G)^t$, where $^t$ is transpose.
Aug 13 at 3:21 comment added Sam Hopkins Not sure if this helps at all with your conjecture, but is it correct that the adjacency matrix of $T$ is the tensor square of the adjacency matrix of $G$?
Aug 12 at 15:15 history edited RobPratt
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Aug 12 at 14:16 history edited Fedor Ushakov CC BY-SA 4.0
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S Aug 12 at 9:51 review First questions
Aug 12 at 10:05
S Aug 12 at 9:51 history asked Fedor Ushakov CC BY-SA 4.0