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Aug 11 at 11:55 comment added Daniel Weber The valuation of the largest prime divisor is 1 with probability of approximately $1 - \frac{1}{\sqrt n}$, right? The sum of $\frac1{\sqrt{n!}$ from $n=100$ is approximately $10^{-79}$, so heuristically this seems very likely (of course, these aren't random numbers)
Aug 11 at 3:50 comment added Gerry Myerson The $A(n)$ are tabulated at oeis.org/A007489 and there are links to tables of factorizations into primes.
Aug 10 at 20:18 history edited Michael Hardy CC BY-SA 4.0
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Aug 10 at 19:53 history asked Marc CC BY-SA 4.0