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Timeline for Boundedness of sum of sin(sin(n))

Current License: CC BY-SA 4.0

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Oct 7 at 21:41 history edited David Roberts CC BY-SA 4.0
links to Z&Z paper
Oct 7 at 15:08 history edited Daniel Asimov CC BY-SA 4.0
Zudlin —> Zudilin
Aug 6 at 17:54 comment added David E Speyer Some corrections: The irrationality measure of $\pi$ is known to be $\leq 7.11$, we don't know how much smaller it might be. All irrational numbers have irrationality measure $\geq 2$. The proof above works with any number with finite irrationality measure. A number with infinite irrationality measure is called a Liouville number en.wikipedia.org/wiki/Liouville_number .
Aug 6 at 15:17 comment added gnasher729 So it seems that every irrational number has some constant telling us how irrational it is, pi has an irrational value 6.11, e might have a different value, and the sum in question is bounded if the value is greater than 2?
Aug 6 at 12:25 comment added David E Speyer The earliest result I can find of this form is Mahler (1953), "On the approximation of $\pi$", who obtains $|\pi - p/q| > c q^{-42}$ and indicates that the exponent can be improved to $30$ but omits the details. ems.press/content/book-chapter-files/27418 The only earlier work that he cites is Feldman (1951) "The approximation of certain transcendental numbers. I. Approximation of logarithms of algebraic numbers" ; I wasn't able to extract a specific bound from Feldman. @PseudoNeo
Aug 5 at 15:54 comment added PseudoNeo Seems that ZZ's bound is overkill for this theorem. How cheaper is it to prove a coarser bound, good enough to do the job? (Differently put: do I have a reasonable chance to make a problem out of this wonderful answer?)
Aug 5 at 14:23 comment added abx If I understand correctly, the only information needed about $\pi$ is that its irrationality measure is finite.
Aug 5 at 13:15 vote accept Oleksandr Liubimov
Aug 5 at 13:08 vote accept Oleksandr Liubimov
Aug 5 at 13:15
Aug 5 at 13:08 comment added Oleksandr Liubimov Mr. David, thank you very much for your solution, the theorems you stated are really nice and useful ! I did not know about them before.
Aug 5 at 12:19 comment added David E Speyer Thanks! I've been wondering whether I can find a $\theta$ for which the sums of $\sin(\sin(n \theta))$ are unbounded. The tricky thing is that, if $\sin(\sin(\phi))$ is close to its maximum, then $\sin(\sin(3 \phi))$ is close to its minimum, so you tend to get a lot of cancellation.
Aug 5 at 12:06 comment added Dave Benson This is a great answer. It shows how the ultimate point is that $\pi$ is not well approximated by rational numbers.
Aug 5 at 12:05 history edited GH from MO CC BY-SA 4.0
edited body
Aug 5 at 11:49 history answered David E Speyer CC BY-SA 4.0