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Aug 6 at 13:45 vote accept Zoltan Fleishman
Aug 5 at 21:08 answer added Steven Sam timeline score: 10
Aug 5 at 13:48 comment added LSpice (I also take the opportunity to mention that my comment should have said that $W(\mathsf D_n)$ contains odd-as-unsigned permutations, not that it doesn't contain even-as-unsigned permutations. That is, my objection should have been that $W(\mathsf D_n) \cap W(\mathsf A_{n - 1})$ isn't the alternating subgroup of $W(\mathsf A_{n - 1})$, not that $W(\mathsf D_n)$ doesn't contain the alternating subgroup of $W(\mathsf A_{n - 1})$; of course the latter is false. @SamHopkins, thank you for reading my comment charitably as it was meant!)
Aug 5 at 13:44 history edited LSpice CC BY-SA 4.0
Hopefully settling the wreath-product issue
Aug 5 at 10:36 comment added Dave Benson The first wreath now looks the wrong way round to me, and the second one just totally wrong because it's not even supposed to be a wreath product.
Aug 5 at 10:31 comment added მამუკა ჯიბლაძე Maybe "special hyperoctahedral group"?
S Aug 5 at 9:58 history suggested Jules Lamers CC BY-SA 4.0
Added second wreath product
Aug 5 at 0:14 comment added Sam Hopkins @LSpice Indeed I now see how that could be confusing. For example, in this paper doi.org/10.37236/1836 the terms "even-signed permutations" and "signed even permutations" are both used, which seems unnecessarily confusing to me.
Aug 4 at 23:11 comment added Zoltan Fleishman Thanks a lot for the $\wr$ edits!
Aug 4 at 22:25 review Suggested edits
S Aug 5 at 9:58
Aug 4 at 17:57 comment added LSpice (By the way, the standard symbol for wreath product is \wr. I edited accordingly.)
Aug 4 at 17:56 comment added LSpice @SamHopkins, re, I'd argue that that terminology is a bit confusing since it sounds like it should include the even permutations, but doesn't.
Aug 4 at 16:21 comment added Sam Hopkins @LSpice: on the other hand "group of even signed permutations" is totally clear and sounds fine, if a bit wordy.
Aug 4 at 16:03 comment added LSpice Every Weyl group has a character that sends all reflections in long/short roots to $-1$, and reflections in short/long roots to $1$. (Which reflections are which depends on whether you call your root system $\mathsf C_n$ or $\mathsf B_n$.) If you call all roots of $\mathsf A_n$ long/short, then this is the sign homomorphism. From this point of view, I'd argue that $W(\mathsf D_n)$ is to the hyperoctahedral group as the alternating group is to $W(\mathsf A_n)$. I'd dare to suggest "alternating hyperoctahedral group", but (1) it's pretty terrible and (2) I've never seen it used.
Aug 4 at 16:00 history edited LSpice CC BY-SA 4.0
Wreath product
Aug 4 at 15:50 comment added Sam Hopkins See en.wikipedia.org/wiki/Hyperoctahedral_group#Subgroups. I don't think there is any standard name for this group like "hyperoctahedral group" or "symmetric group."
Aug 4 at 15:35 history asked Zoltan Fleishman CC BY-SA 4.0