Timeline for When does $\det(\frac{A+A^T}{2})=\det(A)$ for positive-definite $\frac{A+A^T}{2}$?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 4 at 15:00 | comment | added | jlewk | $\|A-B\|^2=\|A\|^2+\|B\|^2-2\langle A,B\rangle$ with $B=A^T$ | |
| Aug 4 at 14:39 | comment | added | Aditya Bandekar | I can follow every step except for the last one. Can you elaborate on how $||A^T-A||^2=0$? I'm probably missing something obvious. | |
| Aug 4 at 9:20 | history | edited | jlewk | CC BY-SA 4.0 |
Aesthetics/clarity
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| Aug 3 at 19:07 | history | answered | jlewk | CC BY-SA 4.0 |