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Aug 3 at 21:12 comment added Dima Pasechnik that's what happens when writing on a mobile phone during childminding, sorry.
Aug 3 at 19:54 comment added LSpice I am a bit confused about casting your $2\times2$ argument as a contradiction—if you remove the assumption $A \ne A^\top$, then it seems to become a direct proof.
Aug 3 at 19:53 history edited LSpice CC BY-SA 4.0
`\operatorname`
Aug 3 at 16:52 history edited Dima Pasechnik CC BY-SA 4.0
typo fix
Aug 3 at 16:16 history answered Dima Pasechnik CC BY-SA 4.0