Timeline for When does $\det(\frac{A+A^T}{2})=\det(A)$ for positive-definite $\frac{A+A^T}{2}$?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Aug 3 at 19:07 | answer | added | jlewk | timeline score: 6 | |
| Aug 3 at 18:02 | vote | accept | Aditya Bandekar | ||
| Aug 3 at 16:16 | answer | added | Dima Pasechnik | timeline score: 2 | |
| Aug 3 at 15:40 | answer | added | Joseph | timeline score: 11 | |
| Aug 3 at 15:22 | history | edited | LSpice | CC BY-SA 4.0 |
it's -> its
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| Aug 3 at 15:02 | history | edited | Aditya Bandekar | CC BY-SA 4.0 |
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| Aug 3 at 15:00 | comment | added | Aditya Bandekar | Yes. If (A+A^T)/2 = A, then we automatically know (A+A^T)/2 = A^T as well because (A+A^T)/2 is symmetric. So yes the equality case is (A+A^T)/2 = A = A^T. I'll edit that into the question. | |
| Aug 3 at 14:57 | comment | added | Dima Pasechnik | that is A=A^T - right? | |
| Aug 3 at 14:50 | history | edited | Aditya Bandekar | CC BY-SA 4.0 |
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| S Aug 3 at 14:47 | review | First questions | |||
| Aug 3 at 15:02 | |||||
| S Aug 3 at 14:47 | history | asked | Aditya Bandekar | CC BY-SA 4.0 |