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Aug 2 at 14:10 comment added Nate River ... I missed that $\mathbb E_{\mathcal G} \mathbb E_{\mathcal G} = \mathbb E_{\mathcal G}$. Nice!
Aug 2 at 13:42 comment added Jochen Glueck @NateRiver: The functions $P_1^n X$ are the elements of your sequence with the odd indices and the functions $P_2^n \mathbb{E}_{\mathcal{H}} X$ are the elements of your sequence with the even indices. If the "odd" and the "even" subsequence both converge almost everywhere to the same function, the entire sequence converges almost everywhere.
Aug 2 at 11:23 comment added Nate River Thanks for the answer! I may be missing something obvious, but how does one obtain the final conclusion from the fact that the two limits coincide?
Aug 2 at 8:58 history answered Jochen Glueck CC BY-SA 4.0