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Aug 2 at 15:04 history became hot network question
Aug 2 at 8:58 answer added Jochen Glueck timeline score: 5
Aug 2 at 7:40 comment added Jochen Glueck Ok, the other Jochen was a minute earlier. ;-)
Aug 2 at 7:39 comment added Jochen Glueck One certainly has strong convergence in $L^2$. (This is true for general orthogonal projections on Hilbert space, not only for conditional expectations, and is, I think, also due to von Neumann. It should be quite straightforward to prove by using the spectral theorem for self-adjoint operators.) I don't know about the almost everywhere convergence, though.
Aug 2 at 7:38 comment added Jochen Wengenroth Von Neumann's theorem about alternating orthogonal projections in Hilbert spaces yields $L^2$-convergence for $X\in L^2$.
Aug 2 at 7:23 history edited Nate River CC BY-SA 4.0
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Aug 2 at 7:17 history edited Nate River CC BY-SA 4.0
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Aug 2 at 7:10 history edited Nate River CC BY-SA 4.0
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Aug 2 at 7:03 history asked Nate River CC BY-SA 4.0