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Jul 28 at 19:48 comment added C00 I see, thanks a lot. I haven't look into the precise mechanics of Spaltenstein's argument, so I'll take a look at that. And yes, absolutely, I do what QCoh(X) to be Grothendieck abelian. So I'm happy to take that for granted.
Jul 28 at 11:19 history edited Leonid Positselski CC BY-SA 4.0
small changes, a typo corrected
Jul 28 at 11:13 history answered Leonid Positselski CC BY-SA 4.0