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Jul 18 at 7:47 comment added Emil Jeřábek @C7X Googology is quite unreliable. It is easy to show that this function is not computable; it is essentially the Kolmogorov complexity of $n$ (and it will be called like that in all other sources). See also cstheory.stackexchange.com/a/42375 .
Jul 18 at 4:02 comment added C7X According to Googology Wiki, there is a sort of inverse of the Busy Beaver function called the Placid Platypus function, whose computability is unknown. This gives a function for which we do not know an algorithm, as opposed to the Busy Beaver function, where we know there can be no algorithm.
Jul 17 at 14:47 history edited Christopher King CC BY-SA 4.0
Unused assumption
Jul 17 at 14:43 comment added LSpice Re, yes, thanks! I also noticed a minor, more easily resolved, issue in the wording for $F(n)$, which I edited to correct.
Jul 17 at 14:42 history edited LSpice CC BY-SA 4.0
Wording for $F(n)$
Jul 17 at 14:42 comment added JoshuaZ @LSpice Well that got completely garbled. Hopefully it now makes more sense.
Jul 17 at 14:42 history edited JoshuaZ CC BY-SA 4.0
fix sentence
Jul 17 at 14:40 history edited LSpice CC BY-SA 4.0
Title of survey
Jul 17 at 12:52 comment added JoshuaZ @HJRW Yeah in these examples, finiteness is trivial. Hence saying at the beginning that this answer is a cheat. Maybe I should have made this a comment and just explicitly asked if they wanted that the finiteness had to be itself non-trivial?
Jul 17 at 12:50 comment added HJRW In both cases, the proof that the number is finite is trivial, no? I interpret the question as asking for non-trivial proofs of finiteness that are non-constructive in that they don't lead to an algoithm (even a very inefficient one) to output the finite set. Admittedly, the question isn't explicit about this, but it seems to me to be the clear implication of the examples given.
Jul 17 at 11:26 history answered JoshuaZ CC BY-SA 4.0