Skip to main content
12 events
when toggle format what by license comment
Jul 17 at 22:13 comment added Isaac @or I have not seen the term "jet" before. Could you explain more? I am more used to the notion of Frechet derivative, which of course should be understood locally (= on local charts) for manifolds. Well, I admit that it can be a little bit awkward for manifolds.
Jul 17 at 17:36 comment added o r Yes, I mean that function. The argument can be applied to show the boundedness of the norms of the higher order derivatives of $\iota$ and $\mu$ as well (higher derivatives are usually described via "jets" in differential geometry).
Jul 17 at 15:44 vote accept Isaac
Jul 17 at 15:42 comment added Isaac @or Plus, I think your argument can be generalized for higher derivatives. That is, $g \to \lVert d^n_g \iota \rVert$ for any $n \in \mathbb{N}$. Here, I have used the notation $d^n_g \iota$ for $n$-order Frechet derivative of $\iota$ evaluated at $g \in G$.
Jul 17 at 15:40 comment added Isaac @or By $\lVert d \iota \rVert$, you mean $g \to \lVert d_g \iota \rVert$ for $g \in G$?
Jul 17 at 15:30 history rollback o r
Rollback to Revision 1
Jul 17 at 15:30 comment added o r @Isaac the norms $\|d\iota\|$ and $\|d\mu\|$ are continuous $\Bbb R$-valued functions on $G$ and $G\times G$. Compactness of $G$ guarantees that their image is bounded.
Jul 17 at 9:48 comment added Isaac @mme I am confused about the domain and range of your differential. Are you thinking pointwise on $G$ or the whole tangent bundle?
Jul 17 at 0:18 comment added mme $d\iota: G \to \Bbb R^\ell$ is a continuous function with compact domain.
Jul 16 at 22:46 history edited Isaac CC BY-SA 4.0
deleted 9 characters in body
Jul 16 at 22:44 comment added Isaac I do not clearly see how we can use compactness of $G$ to show that $\iota: G\to G$ has bounded derivatives. Could you provide more details?
Jul 16 at 22:16 history answered o r CC BY-SA 4.0