Timeline for measure of Haar
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Jul 14 at 22:02 | comment | added | Sean Eberhard | @LSpice Yes. (Also, the phrase "Gelfand pair" was added after I made my comment.) | |
| Jul 14 at 14:58 | comment | added | LSpice | @SeanEberhard, I assume that you have in mind $G = \mathrm S_3$ and $K$ an order-$2$ subgroup. Is that a Gelfand pair? | |
| Jul 14 at 14:52 | comment | added | LSpice |
MathJax note: MathJax does not obey \( \), so \(f\) comes out (f), but, perversely, does obey \\\\( \\\\) (although apparently not in comments: \\\\(f\\\\) shows up as \\\(f\\\) (not a typo!)). See Having the MO Mathjax parser recognise \( \) is a regex away. I have edited accordingly. (Also, the usual spelling is "biinvariant", three 'i's, or "bi-invariant", rather than "binvariant", two 'i's.)
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| Jul 14 at 14:51 | history | edited | LSpice | CC BY-SA 4.0 |
MathJax
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| Jul 14 at 10:21 | review | Close votes | |||
| Jul 20 at 3:03 | |||||
| Jul 14 at 10:09 | history | edited | Ryo Ken | CC BY-SA 4.0 |
added 32 characters in body
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| Jul 14 at 10:07 | comment | added | Ryo Ken | Thank you for your help, my question is it false? | |
| Jul 14 at 10:02 | comment | added | Sean Eberhard | Replacing $x$ with $xy^{-1}$, this is equivalent to saying that $K$-biinvariance implies right invariance with respect to conjugates of $K$. There is a counterexample with $|G| = 6$. | |
| Jul 14 at 9:52 | history | asked | Ryo Ken | CC BY-SA 4.0 |