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Jul 12 at 22:06 comment added Qiuyu Ren @LSpice I'm new to this site. Thanks for letting me know!
Jul 12 at 21:45 comment added LSpice If you find a question more appropriate for MSE, then it is better to vote to migrate (or I think you can flag if you don't yet have privileges to cast such a vote) and answer there, rather than answering in what you feel to be the wrong place.
Jul 12 at 21:44 history edited LSpice CC BY-SA 4.0
`\DeclareMathOperator`
Jul 12 at 20:40 vote accept Linda
Jul 12 at 20:07 history edited Qiuyu Ren CC BY-SA 4.0
added 185 characters in body
Jul 12 at 20:04 comment added Linda Ah, that's a good point. I was being overly clever in attempting to avoid introducing more notation.
Jul 12 at 19:58 comment added Qiuyu Ren The negation signs cancel out: $\omega(-x,-y)=\omega(x,y)$.
Jul 12 at 19:49 comment added Linda Note that I used the antidiagonal embedding taking $x$ to $(x,-x)$. That's why I don't need $-\omega$ on that factor.
Jul 12 at 19:46 history answered Qiuyu Ren CC BY-SA 4.0