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Timeline for A question on Borel measurability

Current License: CC BY-SA 4.0

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S Jul 11 at 4:39 history edited Tobias Fritz CC BY-SA 4.0
improved the statements
S Jul 11 at 4:39 history suggested user532086 CC BY-SA 4.0
improved the statements
Jul 10 at 17:19 answer added David Gao timeline score: 3
Jul 10 at 17:12 comment added David Gao @TobiasFritz $\tau$ may not even be well-defined in that case, since there’s no reason $\{x \in X: \pi(x) = y\}$ is measurable.
Jul 10 at 13:41 review Suggested edits
S Jul 11 at 4:39
Jul 10 at 13:06 comment added Tobias Fritz Without further conditions, aren't there easy counterexamples obtained by equipping $Y = \{0,1\}$ with the indiscrete $\sigma$-algebra $\mathcal{B}_Y = \{\emptyset, Y\}$? Like this, every surjective $\pi$ is measurable, but $\tau$ is not unless it's constant.
Jul 10 at 12:46 history edited bobscott CC BY-SA 4.0
added 43 characters in body; edited tags
S Jul 10 at 12:43 review First questions
Jul 10 at 16:07
S Jul 10 at 12:43 history asked bobscott CC BY-SA 4.0