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Jul 15 at 14:58 comment added Christopher King Note that the "property for Cauchy real implies property for natural numbers" direction is given by using the principles on Cantor set (whose elements are all Cauchy reals).
Jul 7 at 4:28 history became hot network question
Jul 6 at 22:37 answer added Gro-Tsen timeline score: 5
Jul 6 at 21:56 comment added Gro-Tsen Thank you for the clarification. For the record, as evidence that it is not so standard to assume (in the absence of Choice) that Cauchy sequences have a modulus of convergence, I can point to this paper (which explicitly says “Cauchy sequence with modulus” when it assumes one) and that one (which speaks of “regular reals” for the ones defined by a Cauchy sequence with modulus, and “Cauchy reals” for the ones without). So I think it's best to always clarify.
Jul 6 at 21:55 comment added Madeleine Birchfield As for Markov's principle, Toby Bartels made a similar claim on the nLab in 2011 when he wrote on the nLab "Equivalent forms: ... If a Cauchy real number does not equal zero, then it is apart from zero in that it has a multiplicative inverse." but didn't provide a proof or reference for that either.
Jul 6 at 21:46 comment added Madeleine Birchfield @AndrejBauer We do not have countable choice here. We are using the Cauchy real numbers here because that is what Toby Bartels was talking about in 2012 when he wrote on the nLab "In any case, if we use the Cauchy real numbers (sequential real numbers), then the sequential analytic (L)LPO is the same as the (L)LPO for natural numbers." but he did not provide a proof or reference for that statement.
Jul 6 at 21:44 comment added Madeleine Birchfield @Gro-Tsen These Cauchy sequences come with a modulus as that is the convention in constructive mathematics when constructing the Cauchy real numbers as far as I am aware. I have edited the question to clarify that.
Jul 6 at 21:42 history edited Madeleine Birchfield CC BY-SA 4.0
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Jul 6 at 21:31 comment added Gro-Tsen By a “Cauchy sequence” $(u_n)$, do you mean a Cauchy-with-modulus sequence $∃μ:\mathbb{N}\to\mathbb{N}.∀k.∀p,q≥μ(k).|u_p-u_q|<2^{-k}$ or a Cauchy-without-modulus sequence $∀k.∃n.∀p,q≥n.|u_p-u_q|<2^{-k}$ ? Both have been called “Cauchy sequence”, so it would really be best to avoid the term without clarifying it as “with modulus” or “without modulus”.
Jul 6 at 20:57 comment added Andrej Bauer Do we have countable choice? If not, why are we using Cauchy reals?
Jul 6 at 20:28 history asked Madeleine Birchfield CC BY-SA 4.0