Timeline for Is there an elementary proof that the Mertens function is not $O(x^\theta)$ if $\theta <1/2$?
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| Nov 26, 2010 at 21:32 | comment | added | Terry Tao | Note that the function field analogue of M(x) is bounded (no zeroes for the analogous zeta function), so this already rules out a fairly large class of elementary proofs; one needs to somehow use a property of the rational integers that is not shared by the polynomials over a finite field. | |
| Nov 26, 2010 at 18:47 | history | answered | engelbrekt | CC BY-SA 2.5 |