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Jul 4 at 18:05 history edited Will Sawin CC BY-SA 4.0
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Jul 4 at 13:08 history edited Emil Jeřábek CC BY-SA 4.0
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Jul 4 at 8:02 comment added Emil Jeřábek One should be slightly careful in that $[0;a_n,\dots,a_1]$ is not necessarily in the canonical form for a rational continued fraction, as it may end with $1$. (This is why I wrote there are small exceptions to "$a_n=\lfloor a/u\rfloor$" in my comment elsewhere; your answer now makes it clear the exceptions happen when $a/b=[a_0;1,a_2]$.)
Jul 4 at 0:25 history edited Will Sawin CC BY-SA 4.0
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Jul 3 at 20:01 history edited Will Sawin CC BY-SA 4.0
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Jul 3 at 19:54 history answered Will Sawin CC BY-SA 4.0