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Jun 27 at 9:29 comment added Michael Greinecker The approximation goes from compact rectangles to the plane. Differentiability makes no difference there.
Jun 27 at 8:38 comment added Francesco Bilotta @MichaelGreinecker thanks! I have seen the proof. But at some point he writes that the results hold by approximation in the case where the domain is the whole $\mathbb{R}^2$. I was afraid the assumption may come into play therein.
Jun 27 at 8:07 comment added Michael Greinecker There is a proof right after the statement of the theorem. No differentiability assumption is needed.
Jun 27 at 7:59 comment added Akira For the sake of clarity, please add the definitions of "supermodular" and "comonotone".
Jun 27 at 7:48 history asked Francesco Bilotta CC BY-SA 4.0