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Jun 28 at 1:52 comment added Ali Taghavi I am realy curious abiut the reason you impose the condition "The preimage of $\infty$ is nowhere dense" when we are sure that the range of $f$ does not approach infinity
Jun 27 at 20:55 comment added Ali Taghavi Moreover since the algebra $C(X)$ is a commutative model of a von Neumann algebra, I googled "Von neumann algebra + RH" I got some things relevant
Jun 27 at 18:19 comment added Ali Taghavi I am talking about $C^+(X)$ definition
Jun 27 at 18:14 comment added Ali Taghavi How is it possible $f$ take value $\infty$ .?You assumed that $X$ is compact so $f(X)$ is far from the north pole,
Jun 27 at 6:08 comment added new account Isn't "$V^{\mathbb{B}}\models$ the Riemann hypothesis holds" such a statement? Or are you looking for some "functional analytic" statement about the space $C^+(St(\mathbb{B}))$?
Jun 26 at 18:34 review Close votes
Jul 5 at 3:03
Jun 26 at 17:37 history asked Mohammad Golshani CC BY-SA 4.0