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Nov 30 at 12:07 comment added user3840170 Another example to consider: Nelson’s Internal Set Theory. $\{x \in \mathbb R: \forall \varepsilon: \operatorname{st}(\varepsilon) \land \varepsilon > 0 \to |x| < \varepsilon\}$ is not a set by the axiom schema of comprehension, because the predicate used is not a ZFC formula (it contains the symbol $\operatorname{st}$ original to IST) and IST assumes comprehension only for pure ZFC formulæ. Yet it’s clearly not “too large” to be a set, since it’s contained in $\mathbb R$, which is a set. As I remember though, treatments of IST usually call it an “external set” rather than a “proper class”.
Jun 26 at 18:27 history became hot network question
Jun 26 at 13:43 history edited Daniel Asimov CC BY-SA 4.0
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Jun 26 at 11:27 vote accept Mike Battaglia
Jun 26 at 11:23 comment added Mike Battaglia Thanks, I misread that. Still curious about global choice functions though, given the Wikipedia page.
Jun 26 at 11:10 answer added Joel David Hamkins timeline score: 16
Jun 26 at 11:07 comment added Emil Jeřábek Definable with parameters. So all sets are trivially definable.
Jun 26 at 11:02 comment added Mike Battaglia And then there are things like global choice functions, which Wikipedia refers to as proper classes (if they exist); such things are not definable unless $V = HOD$, I think...
Jun 26 at 11:00 comment added Mike Battaglia Do people really use the term this way? So there are sets that aren't definable, but all classes are definable? So undefinable sets would not be classes then?
Jun 26 at 10:53 comment added Wojowu At least in the ZF(C) context, the term "class" is commonly used for a collection of sets which is definable (with parameters). A proper class is any such definable collection which is itself not a set. Separation then asserts that any subclass of a set is itself a set.
Jun 26 at 10:27 history asked Mike Battaglia CC BY-SA 4.0