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Jun 19 at 13:00 comment added Bingyu Zhang @LSpice Sorry, this is a typo. I mean posted.
Jun 19 at 12:59 history edited Bingyu Zhang CC BY-SA 4.0
deleted 1 character in body
Jun 19 at 9:07 comment added YCor If $G=C_{p^\infty}$ then $G\otimes K=0$ for every field $K$. Hence the tensor products with fields will not make any difference between $C_{p^\infty}$ and $\{0\}$.
Jun 19 at 8:40 history became hot network question
Jun 19 at 7:32 answer added Qiaochu Yuan timeline score: 11
Jun 19 at 1:59 comment added LSpice I'm having a little difficulty parsing “It is perfect if the condition C is poseted for all $A \otimes_{\mathbb Z} k$.” The first layer of my confusion is whether you are referring to posets or if this is a typo for “posited”; presumably the latter, but I didn't want to make an assumption.
Jun 19 at 1:58 history edited LSpice CC BY-SA 4.0
Wording
Jun 19 at 0:39 history asked Bingyu Zhang CC BY-SA 4.0