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Bounty Ended with Bazin's answer chosen by CommunityBot
While this is on the front page, typo; removed "thank you"
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LSpice
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Analycity Analyticity of $f*g$ with $f$ and $g$ smooth on $\mathbb{R}$ and analytic on $\mathbb{R}^*$

Suppose that we have two real functions $f$ and $g$ both belonging to $\mathcal{C}^\infty(\mathbb{R},\mathbb{R})$ analytic on $\mathbb{R}\backslash\{0\}$$\mathbb{R}\setminus\{0\}$ but non-analytic at $x=0$. Is the convolution (assumed to be well defined) defined as:

$$(f*g)(x) = \int_\mathbb{R}f(x-z)g(z)dz$$

an analytic function ?

Otherwise, under which conditions the convolution is analytic ?

Any references or solutions will be highly appreciated.

Thank you!

Analycity of $f*g$ with $f$ and $g$ smooth on $\mathbb{R}$ and analytic on $\mathbb{R}^*$

Suppose that we have two real functions $f$ and $g$ both belonging to $\mathcal{C}^\infty(\mathbb{R},\mathbb{R})$ analytic on $\mathbb{R}\backslash\{0\}$ but non-analytic at $x=0$. Is the convolution (assumed to be well defined) defined as:

$$(f*g)(x) = \int_\mathbb{R}f(x-z)g(z)dz$$

an analytic function ?

Otherwise, under which conditions the convolution is analytic ?

Any references or solutions will be highly appreciated.

Thank you!

Analyticity of $f*g$ with $f$ and $g$ smooth on $\mathbb{R}$ and analytic on $\mathbb{R}^*$

Suppose that we have two real functions $f$ and $g$ both belonging to $\mathcal{C}^\infty(\mathbb{R},\mathbb{R})$ analytic on $\mathbb{R}\setminus\{0\}$ but non-analytic at $x=0$. Is the convolution (assumed to be well defined) defined as:

$$(f*g)(x) = \int_\mathbb{R}f(x-z)g(z)dz$$

an analytic function ?

Otherwise, under which conditions the convolution is analytic ?

Any references or solutions will be highly appreciated.

Simplifying conditions
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NancyBoy
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When is the convolution of two elements Analycity of $\mathcal{C}^\infty(\mathbb$f*g$ with $f$ and $g$ smooth on $\mathbb{R},\mathbb$ and analytic on $\mathbb{R})$ an analytic function?^*$

Suppose that we have two real functions $f$ and $g$ both belonging to $\mathcal{C}^\infty(\mathbb{R},\mathbb{R})$ without compact supportanalytic on $\mathbb{R}\backslash\{0\}$ but non-analytic at $x=0$. Is the convolution (assumed to be well defined) defined as:

$$(f*g)(x) = \int_\mathbb{R}f(x-z)g(z)dz$$

an analytic function ?

Otherwise, under which conditions the convolution is analytic ?

Any references or solutions will be highly appreciated.

Thank you!

When is the convolution of two elements of $\mathcal{C}^\infty(\mathbb{R},\mathbb{R})$ an analytic function?

Suppose that we have two real functions $f$ and $g$ both belonging to $\mathcal{C}^\infty(\mathbb{R},\mathbb{R})$ without compact support. Is the convolution (assumed to be well defined) defined as:

$$(f*g)(x) = \int_\mathbb{R}f(x-z)g(z)dz$$

an analytic function ?

Otherwise, under which conditions the convolution is analytic ?

Any references or solutions will be highly appreciated.

Thank you!

Analycity of $f*g$ with $f$ and $g$ smooth on $\mathbb{R}$ and analytic on $\mathbb{R}^*$

Suppose that we have two real functions $f$ and $g$ both belonging to $\mathcal{C}^\infty(\mathbb{R},\mathbb{R})$ analytic on $\mathbb{R}\backslash\{0\}$ but non-analytic at $x=0$. Is the convolution (assumed to be well defined) defined as:

$$(f*g)(x) = \int_\mathbb{R}f(x-z)g(z)dz$$

an analytic function ?

Otherwise, under which conditions the convolution is analytic ?

Any references or solutions will be highly appreciated.

Thank you!

Notice added Draw attention by NancyBoy
Bounty Started worth 50 reputation by NancyBoy
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LSpice
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When is the convolution of two elements of $\mathcal{C}^\infty(\mathbb{R},\mathbb{R})$ an analytic function?

fixed latex in title
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Carlo Beenakker
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NancyBoy
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