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Jun 13 at 17:15 history edited cxrlo CC BY-SA 4.0
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Jun 13 at 17:15 comment added cxrlo Thank you. I actually knew that, and the title was therefore quite misleading. I edited it appropiately.
Jun 13 at 16:28 comment added YCor @MoisheKohan ah indeed. To clarify (to OP): some of the noncompact rank 1 groups have Kazhdan's Property T, but the proof is different (and harder). The first proof is due to Kostant.
Jun 13 at 16:06 comment added Moishe Kohan @YCor: Of course. I was referring to the title question.
Jun 13 at 16:02 comment added YCor @MoisheKohan the proof definitely fails for all rank 1 groups. The proof of Property T for $\mathrm{Sp}(n,1)$ is very different.
Jun 13 at 14:52 comment added Moishe Kohan It does not even fail for all rank 1 groups, just for "most."
Jun 13 at 14:16 comment added YCor Indeed, there is no semidirect product inside ($\mathrm{SL}_2(\mathbf{R})\ltimes\mathbf{R}^2$ in rank one groups. These play an essential role in the proofs (by Harpe-Valette / Bekka-Harpe-Valette and most others).
Jun 13 at 13:49 history edited cxrlo CC BY-SA 4.0
edited title
S Jun 13 at 13:40 review First questions
Jun 13 at 13:41
S Jun 13 at 13:40 history asked cxrlo CC BY-SA 4.0