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Jun 13 at 23:19 vote accept Greg Zitelli
Jun 10 at 21:11 answer added Iosif Pinelis timeline score: 1
Jun 10 at 11:39 comment added Iosif Pinelis Yes. I am still trying to find time to write the answer.
Jun 10 at 6:37 comment added Greg Zitelli @IosifPinelis permutation invariant is enough to show the whole result? You mean without the assumptions on higher moments?
Jun 9 at 1:13 history edited Greg Zitelli CC BY-SA 4.0
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Jun 7 at 3:29 comment added Iosif Pinelis I think "permutation invariant" is enough. I will try to find time to write this up.
Jun 7 at 2:24 comment added Iosif Pinelis "permutation invariant" should have been stated in the original version of your post.
Jun 7 at 2:01 comment added Greg Zitelli @IosifPinelis there are no other conditions missing. Permutation invariant is defined in the first bullet, is it not clear?
Jun 7 at 1:50 comment added Iosif Pinelis "permutation invariant"? What other conditions are missing here? (I asked this in my first comment on this page.)
Jun 7 at 1:44 history edited Greg Zitelli CC BY-SA 4.0
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Jun 7 at 1:35 comment added Greg Zitelli Since it seems confusing I will remove the last part I suppose... I made it clear that the random variables are not iid but are permutation invariant.
Jun 7 at 1:34 history edited Greg Zitelli CC BY-SA 4.0
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Jun 6 at 20:38 comment added Iosif Pinelis I don't understand the equality in your last last display, nor do I know what conditions you are assuming there. Again, are the $X_{N,i}$' s iid? Are the $Y_{N,i}$' s iid? Also, and more importantly, why do you think the convergence of the expected values would imply the convergence in probability??
Jun 6 at 19:44 comment added Greg Zitelli Rephrased and tried to clarify further.
Jun 6 at 19:43 history edited Greg Zitelli CC BY-SA 4.0
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Jun 6 at 19:12 comment added Iosif Pinelis Are $x_{N,1},\dots,x_{N,N},y_{N,1},\dots,y_{N,N}$ random variables? Are $x_{N,1},\dots,x_{N,N},y_{N,1},\dots,y_{N,N}$ jointly independent? Are the $x_{N,i}$'s iid? Are the $y_{N,i}$'s iid? Any other conditions missing? How is it "easy to show"?
Jun 6 at 18:40 comment added Greg Zitelli @DieterKadelka clarified.
Jun 6 at 18:39 history edited Greg Zitelli CC BY-SA 4.0
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Jun 6 at 18:24 comment added Dieter Kadelka I don't understand. What are precisely the assumptions? First, the $x_{N,i}$, $y_{N,i}$ need not be independent? 2. Good measure? 3. $a_n$, $b_n$ finite? 4. $\mathbb{E}|x_{N,i}| = \infty$? $\ldots$
Jun 6 at 17:24 history edited Greg Zitelli CC BY-SA 4.0
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Jun 6 at 16:21 history asked Greg Zitelli CC BY-SA 4.0