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Timeline for When is convergence transitive?

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Dec 18, 2010 at 17:24 comment added rpotrie It is easy to construct an example where $\omega(\omega(X))$ is strictly contained in $\omega(X)$ (consider a rotation of the circle wich attracts a neighborhood in the plane, and multiply the vector field by a bump function which vanishes in a point of the circle). So, if the question is stated as: Does $\omega(X) \subset Y$ and $\omega(Y) \subset Z$ imply $\omega(X) \subset Z$? The answer is no. I guess I had misunderstood the question when I answered it.
Dec 10, 2010 at 17:54 comment added Vincenzo Still thinking about this, sorry... $\omega(\omega(X))$ is certainly contained in $\omega(X)$, but is it always the case that $\omega(\omega(X))=\omega(X)$? If yes, why? And if no, then your argument only proves that $\omega(X)$ and $Z$ intersect, while I need to argue that $\omega(X)$ is contained in $Z$...
Nov 25, 2010 at 10:13 comment added rpotrie If you prefer to put the hipotesis that the omega limit of every point of $X$ is contained (instead of intersects) in $Y$ the same argument works. You should look at the kew word omega limit, see en.wikipedia.org/wiki/Limit_set
Nov 25, 2010 at 10:11 comment added rpotrie Let me try to be more specific: If the equation integrates into a flow (that is, $\varphi_{t+s}(x)=\varphi_t(\varphi_s(x))$) we get that we can define the omega-limit of a point (as the set of points to which the orbit converges) which is an invariant set and the omega limit set of a omega limit set is contained in itself. Consider $x\in X$, then its omega limit intersects $Y$, but since it is invariant and every point of $Y$ has its omega limit intersecting $Z$ we conclude that the omega limit set of $x$ must intersect $Z$ also.
Nov 25, 2010 at 10:04 comment added Vincenzo Thanks rpotrie. For the (high-dimensional) locally Lipschitz case, do you know if the argument you just sketched is formalized in some standard text, or maybe some standard theorem from which it descends immediately?
Nov 25, 2010 at 9:56 vote accept Vincenzo
Nov 24, 2010 at 21:43 history answered rpotrie CC BY-SA 2.5