Timeline for How to check that the surface measure is the weak limit of $\delta^{-1}\mathcal{L}^n|_{B(0,1+\delta)\setminus B(0,1)}$?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 3 at 2:35 | vote | accept | ljjpfx | ||
| Jun 2 at 18:17 | answer | added | Iosif Pinelis | timeline score: 3 | |
| Jun 2 at 13:40 | comment | added | Nate River | Hm, I am thinking of how to use my method to compute it without resorting to spherical coordinates (and thus using circular reasoning), and coming up with nothing, except maybe an ugly partition of unity thing. | |
| Jun 2 at 13:38 | comment | added | ljjpfx | @Nate River Would you like to give the details? Many Thanks! | |
| Jun 2 at 4:11 | comment | added | Nate River | I think you can prove it by estimating the integral of a continuous function over $B(0, 1 + \delta) \setminus B(0, 1)$ by its values on $\partial B(0, 1)$, using the formula for the volume of a ball to bound the error. | |
| Jun 1 at 23:44 | history | asked | ljjpfx | CC BY-SA 4.0 |