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Jun 5 at 9:58 comment added Nathan Chappell @provocateur I've added a section on infinite types. Let me know what you think!
Jun 5 at 9:58 history edited Nathan Chappell CC BY-SA 4.0
Stuff on infinite types.
Jun 5 at 1:49 comment added provocateur Well I guess the question is whether it helps us make sense of the idea that incompleteness is a consequence of 'the fact that the formation of ever higher types can be continued into the transfinite', which was OP's question. I guess on the diagnosis you are considering incompleteness is due to the fact that the type of the diagonal lemma is inhabited. At first glance these seem to be quite different diagnoses, though I am open to being convinced otherwise.
Jun 4 at 22:39 comment added Nathan Chappell @provocateur $Y$ not?
Jun 4 at 22:37 history edited Nathan Chappell CC BY-SA 4.0
added 598 characters in body
Jun 4 at 22:28 comment added provocateur Fair enough, I guess it is true that in strong typing systems, the type corresponding to the diagonalization lemma will be inhabited, while in weak systems it is not. From the Curry Howard Correspondence, this just follows fairly directly from the fact that in weak theories the diagonalization lemma is not provable, while in sufficiently strong theories it is. I guess the question is what we gain from viewing all this in terms of the Curry Howard Correspondence and type inhabitation, rather than just from the point of view of first order theories.
Jun 4 at 7:50 comment added Nathan Chappell @provocateur Are you familiar with Curry-Howard? The idea of propositions as types comes from that. It's untypable in the simply typed lambda calculus (and some extensions that essentially introduce other "logical connectives" than ->). It's typable in other systems. I don't know about other's making the claim, I guess I didn't even consider it to be a claim and more of an observation. I'll put up an explanation a little later, although we're going to need to use $\beta$ reduction...
Jun 4 at 7:12 comment added provocateur I'd love for this to be a precise and rigorous claim, but right now I just don't see it. I don't know what it means to say both that Y is untypeable and that its type is the diagonalization lemma. Has this claim been made in the literature by anyone?
Jun 3 at 7:46 history edited Nathan Chappell CC BY-SA 4.0
Additional explanation, remove superflous narrative
Jun 3 at 6:49 comment added Nathan Chappell @provocateur The type of the Y combinator is the diagonalization lemma, the combinator Y itself is the proof of the lemma. That's not really a claim, that's the interpretation of the Curry-Howard isomorphism... What I'm claiming is about what Goedel might have meant and showing the relationship to type theory in case it's of interest.
Jun 2 at 23:24 comment added provocateur So is the claim is that there is a connection between the Y combinator and the diagonalization lemma (the theorem you quote from Kunen)? If so, what is the precise connection? For example, does using the untypeability of the Y combinator give us an easy proof of the diagonalization lemma? That is not obvious to me. Or is the connection supposed to be something else?
Jun 2 at 14:12 comment added Nathan Chappell @provocateur I added a new section, please let me know if it needs to be further elaborated.
Jun 2 at 14:12 history edited Nathan Chappell CC BY-SA 4.0
Clarify relationship of Y and Incompleteness
Jun 2 at 0:22 comment added provocateur The exact connection between the untypability of Y and Godel Incompleteness is not clear to me at all.
Jun 1 at 17:17 history edited Martin Sleziak CC BY-SA 4.0
fixed a link to a comment
Jun 1 at 17:06 history edited LSpice CC BY-SA 4.0
Links to comments, inclined commutative diagram, and other tidying
S Jun 1 at 17:02 review First answers
Jun 1 at 20:15
S Jun 1 at 17:02 history edited Nathan Chappell CC BY-SA 4.0
typos
S Jun 1 at 12:19 review First answers
Jun 1 at 12:26
S Jun 1 at 12:19 history answered Nathan Chappell CC BY-SA 4.0