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Jun 6 at 4:44 comment added AGenevois I think so. And probably not only for spheres, but also for arbitrary manifolds (with respect to a sufficiently good triangulation).
Jun 5 at 8:00 comment added Marcos I was thinking about something that looks trivially true but I have no idea how to prove. In the same spirit of this example there must exist a triangulation of the $n$-sphere with no disconnecting stars nor two distinct vertices such that the link of one is contained in the star of the other, right? (Thanks for the correction)
May 29 at 14:12 vote accept Marcos
May 29 at 14:10 vote accept Marcos
May 29 at 14:11
May 29 at 12:48 history answered AGenevois CC BY-SA 4.0