Timeline for Solution to the Eikonal equation with almost everywhere continuous derivative
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 28 at 7:43 | vote | accept | Nate River | ||
| May 28 at 7:43 | comment | added | Nate River | Ah uniqueness would do it… | |
| May 28 at 5:23 | comment | added | Guido De Philippis | It follows from uniqueness, if $x_k\to x$ and $\pi(x_k)\to y$, then it is easy to see that $y$ realizes the distance and so it has to coincide with $\pi(x)$. | |
| May 28 at 5:20 | history | edited | Guido De Philippis | CC BY-SA 4.0 |
Corrected the formula for the gradient
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| May 27 at 20:46 | comment | added | Nate River | Thanks for the answer! Is it obvious that $x - \pi(x)$ is continuous at any point of differentiability? Having trouble showing this formally. | |
| May 27 at 20:44 | vote | accept | Nate River | ||
| May 27 at 20:45 | |||||
| May 27 at 16:43 | history | answered | Guido De Philippis | CC BY-SA 4.0 |