Skip to main content
44 events
when toggle format what by license comment
Jul 11 at 6:17 history edited pie CC BY-SA 4.0
added 2913 characters in body
S Jun 5 at 3:29 history bounty ended pie
S Jun 5 at 3:29 history notice removed pie
Jun 4 at 1:04 history edited pie CC BY-SA 4.0
added 105 characters in body
Jun 1 at 23:27 answer added Saúl RM timeline score: 5
Jun 1 at 23:26 comment added pie BTW I don't know if this is useful or not but the triangle with sides $1, \ 0.7239, \ 0.365808$ the point of convergence is very close to the obtuse angle
Jun 1 at 22:50 comment added Saúl RM I will leave an answer shortly explaining a bit more
Jun 1 at 22:25 comment added pie @SaúlRM What is the thing special about $1,0.05730946,0.959413912$ that make the sequence diverge (How did you discover it?)? and what are these numbers ? Graphing this triangle seems to diverge but I have my doubts
Jun 1 at 21:08 comment added Saúl RM Also, it seems like in most cases (likely except in some measure $0$ subset of the set of triangles, if you give some reasonable measure to the set of triangles), the ratio between the sides of the triangles will converge to something close to $(1:0.31720:0.85873)$. And then your Scenario 1 will be satisfied, and the triangles will converge to a point. But convergence to the ratios I mentioned above is very slow
Jun 1 at 20:28 comment added Saúl RM It looks like for a triangle whose side lengths are some values close to $1,0.05730946,0.959413912$, the $9^{\text{th}}$ iteration is an isometric copy of the original triangle but around $5$ times bigger. This means that this triangle would satisfy your scenario $3$: "The points will completely diverge". That said, 1) I am worried about the precision of my geogebra, especially since the 4$^{\text{th}}$ iteration of the triangle I mention is almost degenerate. 2) I'm not even going to try to prove it rigorously
May 31 at 2:47 comment added Gerry Myerson 19th version of this question.
May 31 at 0:43 history edited pie CC BY-SA 4.0
added 4 characters in body
May 30 at 20:38 comment added pie @DarrenLi The area is not strictly decreasing
May 30 at 14:24 comment added GChromodynamics Is it possible to prove that the area is strictly decreasing?
May 30 at 10:59 history edited pie CC BY-SA 4.0
deleted 1 character in body
May 30 at 10:25 history edited pie CC BY-SA 4.0
deleted 15 characters in body
May 29 at 15:17 history edited pie CC BY-SA 4.0
added 120 characters in body
May 29 at 11:24 history edited pie CC BY-SA 4.0
added 25 characters in body
May 29 at 1:48 comment added pie @crow It seems that the limit point is not any of the centers listed in ETC.
May 29 at 1:34 history edited pie CC BY-SA 4.0
added 479 characters in body
May 28 at 19:35 history edited pie CC BY-SA 4.0
added 144 characters in body
May 28 at 14:50 history edited pie CC BY-SA 4.0
deleted 5 characters in body
May 28 at 14:44 history edited pie CC BY-SA 4.0
deleted 5 characters in body
May 28 at 14:34 history edited pie CC BY-SA 4.0
edited title
S May 28 at 14:32 history bounty started pie
S May 28 at 14:32 history notice added pie Draw attention
May 28 at 13:49 history edited pie CC BY-SA 4.0
added 18 characters in body
May 27 at 17:33 comment added Gro-Tsen This is reminiscent of a kind of “iterated mean” process (see this question on this subject), but in dimension 2 and invariant under Euclidean similitudes rather than in dimension 1. To prove convergence you probably need to rephrase it as a map in the modulus space of triangles, but it is unlikely that the point will have interesting properties, as already the arithmetic-quadratic mean of two real numbers is largely unstudied (as per previously linked question).
May 27 at 17:30 comment added Pietro Majer @crow i’d say a bit less ${40000 \choose 3}+40000^2$; still enough, for a while (then we may iterate)
May 27 at 16:56 history edited pie CC BY-SA 4.0
added 76 characters in body
May 27 at 13:57 comment added pie @PietroMajer It is not defined, in fact if the sequence reached a degenerate triangles starting from a non-degenerate one the sequence will stop as I sated in the point 4
May 27 at 12:36 comment added Pietro Majer How is the map defined for degenerate triangles, e.g. if A, B, C are collinear? (or maybe this never happens starting from a non-degenerate triangle?)
May 27 at 12:27 history edited pie CC BY-SA 4.0
added 4 characters in body
May 27 at 12:08 history edited pie CC BY-SA 4.0
added 9 characters in body
May 27 at 7:15 comment added crow @Daniel Asimov It appears to ocillate between approximations to two specific triangles. Again this is based on a few crude simulations so pure speculation. But the dynamics of the iteration proposed by the OP seem to be quite fascinating.
May 26 at 20:05 comment added Daniel Asimov If the sequence of points converges to a point, it is possible that (considering angles alone) it converges to a specific triangle. (Or not.)
May 26 at 19:09 history edited pie CC BY-SA 4.0
deleted 141 characters in body
May 26 at 16:06 history edited pie CC BY-SA 4.0
added 280 characters in body
May 26 at 16:04 comment added pie @crow If the triangles converge to a point this point is unique to the triangle, I wonder what extra properties this point have. The only point (which is very unique to a triangle) that I didn't include is the circumcenter but this sequence doesn't converge to it.
May 26 at 15:31 comment added crow Well, if my simulations are anything to go by, the iterates of $\Phi$ tend to $(0,0,0)$ for triangles of very different shapes (i.e., the triangles converge to a point), in rather interesting ways, and so I will stick my neck out and conjecture that this is the case for any shape.
May 26 at 14:11 comment added crow If we denote the sides lengths of $A_1B_1C_1$ by $a_1,b_1 ,c _1$ and those of $A_2B_2C_2$ by $a _2,b_2 ,c _2$, then this defines in a natural way a mapping $\Phi$ on three space and your question is asking for the dynamics of its iterates. It is possible to compute $\Phi$ explicitly (I have done so) but the expression is rather complicated and I have no idea about its dynamics. However, one can use it for some simulations. The few attempts that I have made look as if they are going to a point but they are hardly enough to use even as the basis for a conjecture.
May 26 at 14:05 history edited pie CC BY-SA 4.0
deleted 2 characters in body
May 26 at 14:02 history edited LSpice CC BY-SA 4.0
tingle -> triangle
May 26 at 12:26 history asked pie CC BY-SA 4.0