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May 28 at 9:13 comment added Zuhair Al-Johar @ElliotGlazer Yes! I should have added that the incomparability to pure sets condition must be changed to non-subnumerosity to pure sets.
May 28 at 8:25 comment added Elliot Glazer Even Z (without foundation) is enough to prove the standard equivalences of choice, e.g. AC iff Well-ordering Thm iff cardinal trichotomy iff surjective cardinal trichotomy.
May 27 at 14:14 vote accept Zuhair Al-Johar
May 27 at 14:14 history edited Zuhair Al-Johar CC BY-SA 4.0
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May 26 at 18:05 history edited Zuhair Al-Johar CC BY-SA 4.0
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May 26 at 17:49 history edited Zuhair Al-Johar CC BY-SA 4.0
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May 26 at 17:35 comment added Zuhair Al-Johar Yes! You are right. The question should be about ZCA. Anyhow.
May 26 at 17:34 vote accept Zuhair Al-Johar
May 26 at 17:49
May 26 at 17:29 history edited Zuhair Al-Johar CC BY-SA 4.0
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May 26 at 14:20 history became hot network question
May 26 at 13:48 answer added Joel David Hamkins timeline score: 8
May 26 at 12:33 comment added Monroe Eskew A set theory with Choice that permits incomparable cardinalities just seems to be missing an axiom.
May 26 at 11:57 history edited Zuhair Al-Johar CC BY-SA 4.0
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May 26 at 6:15 history asked Zuhair Al-Johar CC BY-SA 4.0