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May 29 at 5:16 vote accept yanqing
May 29 at 2:31 answer added Ian Agol timeline score: 4
May 29 at 2:07 comment added Ian Agol @yanqing: No, this construction will be compressible only from one side.
May 25 at 6:23 comment added yanqing Thank you, Ian. If I understand your example correctly, $\partial N$ is compressible from both sides. May I ask that: will the diameter of $N$ be bounded by the diameter of $\partial N$ if $\partial N$ is separating and incompressible from one side?
May 23 at 18:55 comment added Ian Agol No, this won’t hold in general. One may construct manifolds with $\pi(N)$ of unbounded diameter and $\pi(\partial N)$ bounded diameter. I might try to write a more complete answer, but to summarize: one may take a hyperbolic handlebody with convex core $N$ and $\partial N$ of bounded diameter but $N$ of arbitrarily large diameter. Perturb a bit so that one may extend by a reflection group using Thurston’s reflection trick, then a manifold cover will have $N$ embedded and hence won’t satisfy your conditions.
May 21 at 22:18 history edited yanqing CC BY-SA 4.0
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May 21 at 22:18 comment added yanqing Sorry, I should delete the regular hypothesis.
May 21 at 20:18 comment added HJRW So presumably you want to delete the “regular” hypothesis too?
May 21 at 15:22 review Close votes
Jun 5 at 3:02
May 21 at 6:40 history edited yanqing CC BY-SA 4.0
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May 21 at 5:42 comment added HJRW Also, since $M$ is closed, all diameters in $M$ are finite.
May 21 at 5:36 comment added HJRW It can’t be a regular cover. Any finitely generated non-trivial normal subgroup of $\pi_1(M)$ is a closed surface group or a 3-manifold group.
May 21 at 5:17 history asked yanqing CC BY-SA 4.0