Timeline for A question about spectral sequences
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Jun 5 at 8:31 | comment | added | Mehmet Onat | You are right. It is not true. | |
| Jun 3 at 22:16 | comment | added | Nicholas Kuhn | @MehmetOnat Why do you think that the map $E_{\infty}^{p,0} \otimes E_{\infty}^{0,q} \rightarrow E_{\infty}^{p,q}$ should be an isomorphism? | |
| May 22 at 9:11 | comment | added | Mehmet Onat | Isn't the $H^*(B_G)$-module generated by $E_{\infty}^{0,*}$ already a free $H^*(B_G)$-module? $E_2^{*,0}=H^*(B_G)$ and the multiplication is given by $E_{2}^{p,0}\otimes E_{\infty }^{0,q}=E_{\infty }^{p,0}\otimes E_{\infty }^{0,q}=E_{\infty }^{p,q}\subset H^{p+q}\left( M_{G}\right) $? | |
| May 20 at 20:19 | history | edited | Nicholas Kuhn | CC BY-SA 4.0 |
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| May 20 at 20:01 | history | edited | Nicholas Kuhn | CC BY-SA 4.0 |
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| May 20 at 19:28 | history | answered | Nicholas Kuhn | CC BY-SA 4.0 |