Timeline for Injectivity of a convolution operator
Current License: CC BY-SA 4.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 17 at 15:18 | comment | added | Ribhu | the Fourier transform of $f$ may not be defined. Note that $f$ belongs to a weighted $L^2$ space, so $f$ may not belong to $L^1(\mathbb{R})$ or $L^2(\mathbb{R})$. | |
| S May 17 at 8:19 | review | First answers | |||
| May 17 at 9:27 | |||||
| S May 17 at 8:19 | history | answered | Damien | CC BY-SA 4.0 |