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May 16 at 14:41 comment added JimmyJames I'm surely missing the point here but isn't that process deterministic? Is that really just 'reordering' instead of 'shuffling'? A 'perfect' shuffle isn't really a shuffle at all. For example, if you execute perfect riffle shuffles repeatedly, the deck eventually returns to its original order.
May 15 at 15:13 history became hot network question
May 15 at 13:06 history edited Dominic van der Zypen CC BY-SA 4.0
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May 15 at 13:04 vote accept Dominic van der Zypen
May 15 at 13:04 comment added Dominic van der Zypen Thanks @ChrisWuthrich -- my son just found an inconsistency in ${\sf (ZF)}$ and will publish it before going back to afternoon school
May 15 at 10:33 answer added Will Sawin timeline score: 14
May 15 at 9:31 comment added Chris Wuthrich Congratulations to your son's rediscovery of a shuffle that Monge wrote a paper about in 1773 according to p 107 in W.W. Rouse Ball's book
May 15 at 9:20 history edited Dominic van der Zypen CC BY-SA 4.0
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May 15 at 8:23 history edited Dominic van der Zypen CC BY-SA 4.0
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May 15 at 8:21 comment added Dominic van der Zypen Thanks @PeterTaylor, will remove question 2
May 15 at 7:40 comment added Peter Taylor That answers question 2, because we have $2^{\operatorname{ord}(\text{sh}_n)} + 1 \ge 4n + 1$, so $\operatorname{ord}(\text{sh}_n) \ge 2 + \lg n$.
May 15 at 7:32 comment added Peter Taylor oeis.org/A019567
May 15 at 7:13 history asked Dominic van der Zypen CC BY-SA 4.0