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May 14 at 12:20 comment added Licheng Zhang Thank you. What I often consider is the first type, unlabeled. Moreover, for $k$-planar graphs, this need will increase. For example, traverse different non-isomorphic 1-planar drawings of some graphs of low-order. (Two drawings of a graph are isomorphic if there is a homeomorphism of the sphere that maps one drawing to the other. )
May 14 at 4:58 history answered Brendan McKay CC BY-SA 4.0