Timeline for Is the mapping space from $\Delta[k]$ to a simplicial set $X$ weak equivalent to $X$?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 10 at 15:52 | comment | added | Fernando Muro | The map $\Delta[k]\rightarrow *$ is a homotopy equivalence. | |
| May 10 at 15:31 | comment | added | SetR | @FernandoMuro I suspected this must be the reason but I don't see how to use the fact that $\Delta[k]$ is contractible to prove this. Do you know of a reference? | |
| May 10 at 15:16 | comment | added | Fernando Muro | 1. Yes, because $\Delta[k]$ is contractible. 2. Yes, at least if $X$ is a Kan complex, because the inclusion of vertices in $\Delta[k]$ is a cofibration. | |
| May 10 at 15:04 | history | asked | SetR | CC BY-SA 4.0 |