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May 17 at 10:04 comment added HJRW I think your answer is still interesting! But you might like to edit it to make it clear that it doesn't quite answer the question as stated.
May 17 at 9:26 comment added M. Dus @HJRW Thank you very much, I had misread the question. But for hyperbolic groups, the Floyd boundary is the Gromov boundary.... I asked the OP in comments if they really assume that the group is hyperbolic and if so I will delete my answer.
May 16 at 16:42 comment added HJRW The question assumes the group is hyperbolic.
May 10 at 9:29 history answered M. Dus CC BY-SA 4.0