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May 12 at 15:21 vote accept tom jerry
May 10 at 0:30 history edited Saúl RM CC BY-SA 4.0
Wrote a more illuminating proof
May 9 at 16:08 comment added Saúl RM Of course, what I prove is more general (if $k_1>1$, that just means that the set $B$ of my answer can be expressed as a product)
May 9 at 15:56 comment added tom jerry Thank you! And moreover, could this implies that when k_1 larger than √k (but not let k_1=1) , the question is negative?
May 9 at 15:30 comment added Saúl RM I am sure there is a much more elegant way to write my answer, for now I just wrote the first thing that came to mind. I will surely try to write something nicer later if noone does it first
May 9 at 15:29 history edited Saúl RM CC BY-SA 4.0
added 664 characters in body
May 9 at 14:45 comment added Saúl RM Oh sorry, when I read `hypersquare' I had thought it would be a product of intervals. The construction will still work I think, I will write why
May 9 at 14:13 comment added tom jerry Thanks for your answer, however, $U_i$ needn't to be an interval--it is just a subset of [0,1].
May 9 at 11:12 history answered Saúl RM CC BY-SA 4.0