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May 8 at 7:22 comment added Andrej Bauer @DominicvanderZypen: all is well, you seem to be past the first stage :-)
May 8 at 6:48 comment added Dominic van der Zypen @AndrejBauer I am only an amateur mathematician - please cut me some slack :)
May 8 at 6:46 comment added Dominic van der Zypen You guys don't seem to like contradiction. In Switzerland we have direct democracy, people can vote on stuff, loads of debates, so a contradictory lifestyle is in my DNA.
May 7 at 20:55 comment added Andrej Bauer Horrible, horrible unecessary use of proof by contradition. Straight induction would have worked.
May 7 at 14:10 comment added Sam Hopkins You also really don’t need to phrase the proof as by contradiction. Anyways, the question itself is off topic here so it doesn’t need a perfect answer.
May 7 at 12:46 history edited Dominic van der Zypen CC BY-SA 4.0
simplified the argument after suggestion by user @LSpice
May 7 at 12:45 comment added Dominic van der Zypen Thanks @LSpice - will use the shortcut you mention
May 7 at 12:12 comment added LSpice I think it doesn't matter for your last paragraph that $n_0 > 1$, as opposed to $n_0 > 0$. That is, you don't need to handle the $n_0 = 1$ case separately.
May 7 at 11:55 history edited Sam Hopkins CC BY-SA 4.0
added 14 characters in body
May 7 at 11:22 comment added Dominic van der Zypen It was a pleasure - and welcome to MathOverflow!
May 7 at 9:37 comment added Andrew S. Great answer, thank you so much!)
May 7 at 9:37 vote accept Andrew S.
May 7 at 9:30 history answered Dominic van der Zypen CC BY-SA 4.0