Timeline for Subset of a complex manifold whose intersection with every holomorphic curve is analytic
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| May 9 at 13:43 | comment | added | Luka Thaler | @ThomasKurbach Indeed, you are totally right! I was to fast with my comment. | |
| May 8 at 14:14 | comment | added | Thomas Kurbach | @LukaThaler That does not work, because the complex curve $\left\{(z,z)\mid z \in \mathbb{C}\right\}$ intersects your $A$ in the real analytic curve $\left\{(x,x)\mid x \in \mathbb{R}\right\}$. | |
| May 8 at 13:13 | comment | added | Luka Thaler | Please correct me if I'm wrong but I will assume that by analytic set you mean complex analytic? If that is the case, what happens if you take X=\mathbb{C}^2 and A=\{ (z, \overline{z}) | z\in \mathbb{C} \} ? Clearly A is not analytic (it is real analytic - even real algebraic), and since holomorphic curves are also analytic (and therefore also real analytic) their intersection will consist of discrete set of points. | |
| May 6 at 21:08 | history | became hot network question | |||
| May 6 at 17:06 | comment | added | V. Rogov | I guess, an image of a nonconstant map of a Riemann surface. The question is local, so it is enough to check on embedded holomorphic discs. | |
| May 6 at 17:04 | history | edited | V. Rogov | CC BY-SA 4.0 |
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| May 6 at 15:06 | comment | added | Moishe Kohan | What exactly do you mean by a holomorphic curve? Do you mean the image of a nonconstant holomorphic map of a Riemann surface? Do you mean a properly embedded complex 1-dimensional submanifold? ... | |
| May 6 at 15:03 | history | edited | Moishe Kohan | CC BY-SA 4.0 |
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| May 6 at 14:29 | history | edited | Francesco Polizzi | CC BY-SA 4.0 |
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| May 6 at 14:09 | answer | added | Francesco Polizzi | timeline score: 3 | |
| May 6 at 13:06 | history | asked | V. Rogov | CC BY-SA 4.0 |