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Jul 12 at 13:27 history edited Notamathematician CC BY-SA 4.0
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May 7 at 17:53 vote accept Notamathematician
May 7 at 11:41 answer added Peter Taylor timeline score: 4
May 7 at 10:35 comment added Peter Taylor My Sage code. I've generalised the binomial coefficients to an arbitrary triangle of coefficients $C_{n,k}$ and it still seems to work. Note that for your final question, $k$ is just $C_{1,0}$. I observe that the process can be rewritten by taking $t$ to be an infinite sequence of $1$s and then for each bit in $n$, most significant first, if it's a $1$ we multiply by the triangular matrix $C$ and if it's a $0$ we shift off the first element of $t$. The result is $t_0$ after the process completes.
May 7 at 6:33 comment added Notamathematician @PeterTaylor, thank you for comment! Done. Here $L$ is the number of $0$s in the binary expansion of $2n$.
May 7 at 6:30 history edited Notamathematician CC BY-SA 4.0
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May 6 at 11:02 comment added Peter Taylor I presume in the definition of $L$ that the bound variable should be $k$ rather than $i$, but I'm not sure about the indexing of $T$. Is $L$ the number of $1$s in the binary expansion of $2n$, or the number of $0$s?
May 4 at 18:48 history asked Notamathematician CC BY-SA 4.0