Timeline for Extracting a subsequence Cesàro converging to the limsup of the Cesàro sums
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 4 at 14:37 | history | edited | LSpice | CC BY-SA 4.0 |
Typo
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| May 4 at 12:55 | vote | accept | Nate River | ||
| May 4 at 12:55 | comment | added | Nate River | Oh never mind. I misread the construction. What you suggested works. Nice construction! | |
| May 4 at 12:50 | comment | added | an_ordinary_mathematician | If you need more details I can write down all the $\epsilon, \delta$ 's | |
| May 4 at 12:49 | comment | added | an_ordinary_mathematician | Its a bit messy to write down, but the idea is that if the interval $ [m_k, m_{k+1}) $ is much longer than the interval $[1,m_k)$, when you average the only part of the sequence that counts is in the r.v. having index in the longer interval. | |
| May 4 at 12:42 | comment | added | Nate River | Hm why is $Y = 1$ on $(\frac{1}{2}, 1)$? It seems I get $Y = 1$ on $(0, \frac{1}{2})$ and $0$ otherwise. | |
| May 4 at 11:52 | history | answered | an_ordinary_mathematician | CC BY-SA 4.0 |