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May 5 at 10:36 vote accept Nikolai
May 4 at 14:38 history edited LSpice CC BY-SA 4.0
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May 4 at 13:04 comment added Nikolai You're right, that's a bit problematic. Using the parallelity of $\omega$ as Jeffrey mentioned, would not need these assumptions on compactness and connectedness? @DavidESpeyer
May 4 at 12:51 comment added David E Speyer Your argument for $\Delta \eta = 0$ implies $\Lambda \eta$ constant seems to assume that $X$ is compact and connected? If $X$ is not compact, then $\Delta(\phi)=0$ doesn't imply $\phi$ locally constant (EG $X = \mathbb{C}$ and $\phi$ any holomorphic function) and, of course, if $X$ is disconnected, than locally constant doesn't imply constant.
May 4 at 11:37 answer added Jeffrey Case timeline score: 6
May 4 at 8:59 history edited Nikolai CC BY-SA 4.0
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May 4 at 8:49 history asked Nikolai CC BY-SA 4.0