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Sep 28, 2017 at 11:43 vote accept Jeff Strom
Sep 27, 2017 at 16:21 answer added Jon Barmak timeline score: 11
Sep 27, 2017 at 13:15 comment added Jeff Strom This arxiv.org/abs/1709.08734 came up on the arXiv today. I hope Jonathan Ariel Barmak will post soon and collect his checkmark.
Feb 5, 2014 at 20:20 comment added Lennart Meier Great! So in particular, singular cohomology is not represented by any $T_1$-space in the homotopy category of spaces.
Nov 23, 2010 at 14:22 comment added Tom Goodwillie If the space $Y$ is also a $T_1$ space, then its path components are weakly contractible, by choosing $A=S^n$, $n>0$, and $B$ a suitable space with finitely many points. Each of these path components is then contractible, by choosing $A$ to be the path-component and $B$ to be a point. For any two path components there is a sequence in one converging to a point in the other, by choosing $B=${0,1, 1/2, 1/3,...} and $A$ discrete. Thus $Y$ is either connected or empty. Can one take this further and see that then $Y$ is either or contractible or empty?
Nov 23, 2010 at 7:38 answer added Neil Strickland timeline score: 6
Nov 23, 2010 at 2:23 history edited Jeff Strom CC BY-SA 2.5
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Nov 23, 2010 at 2:15 history asked Jeff Strom CC BY-SA 2.5